Chemistry End of Chapter 3 ?s

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chibean
Posts: 11
Joined: Fri Jan 03, 2020 12:10 pm

Chemistry End of Chapter 3 ?s

Post by chibean » Mon Feb 17, 2020 12:16 pm

For this problem:
How many ions are expected to be present in a 1 L solution of 1.5 M NaCl? Assume ions present due to the dissociation of water are negligible.
Could you explain the steps to solve this in more detail?
NS_Tutor_Mathias
Posts: 616
Joined: Sat Mar 30, 2019 8:39 pm

Re: Chemistry End of Chapter 3 ?s

Post by NS_Tutor_Mathias » Thu Feb 20, 2020 2:20 pm

1 mole of anything = 6.022 * 10^23 individual particles

So:
1.5 M * 1L = 1.5 mol NaCl

Each NaCl dissociates into 2 ions, so
1.5 mol NaCl * 2 = 3 mol ions

Each mol is a count of 6.022 * 10^23 particles
3 mol ions * 6.022 * 10^23 particles/mol = 18 * 10^23 = 1.8 * 10^24 ions
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